Note: Answers may be longer than I would deem sufficient on an exam. Some might vary slightly based on points of interest, examples, or personal experience. These suggested answers are designed to give you both the answer and a short explanation of why it is the answer.
Utility functions represent preferences, which themselves are simply rankings bundles against other bundles–any two bundles must have 1 bundle preferred to the other, or indifference between the two. So, utility functions are ordinal in that the numbers outputted by a utility function \(u(x)\) for a particular bundle have no meaning in and of themselves, and there can be no meaningful mathematical operation done on them. Their only interpretation is for comparison: if bundle \(x\) is preferred to bundle \(y\), then the utility of bundle \(x\) is higher than the utility of bundle \(y\).
Since we only care about ordinal ranking, that is \(u(x)>u(y)\), we can have multiple utility functions (e.g. \(v\)) that validly represent the same preferences, so long as \(v(x)>v(y)\) also. To be technical, this only works for positive monotonic transformations of utility functions, like adding a constant, multiplying by a constant, cubing, taking logs, etc.
The marginal rate of substitution (MRS) is the subjective tradeoff (or exchange rate) between two goods in the mind of a consumer (based on their preferences). The number literally means the amount of good \(y\) the consumer is willing to give up (rate of substitution) to get 1 more (marginal) unit of \(x\).
The \(MRS=\frac{MU_x}{MU_y}\) is the slope of the indifference curves, which express one level of utility of a consumer’s utility function given their preferences. The slope of the budget constraint \(\frac{p_x}{p_y}\) is the rate at which the market trades off (or exchange rate) between \(x\) and \(y\), based on relative prices.
At the optimum consumption point, the consumer maximizes their utility (reaches the highest possible indifference curve) subject to their income (they spend all of their money) – thus their optimum is at a point where the their utility function and budget constraint are tangent. At a tangency, the slopes between the budget constraint and the indifference curve are the same.
\[\begin{aligned} |\text{Slope of Indifference Curve}| &= |\text{Slope of Budget Constraint}|\\ \frac{MU_x}{MU_y}&=\frac{p_x}{p_y}\\ \end{aligned}\]
We have seen equivalently that at this point:
\[\frac{MU_x}{p_x}=\frac{MU_y}{p_y}\]
This means intuitively that at the optimum, the marginal utility (value) earned for every additional dollar spent on either \(x\) or \(y\) is the same. That is, you can get no more utility by spending a dollar more on \(x\), or by spending a dollar more on \(y\). This combination is the best that you can possibly do.
If this was not true, for example if you could get more utility by spending more money on \(x\), then \(\frac{MU_x}{p_x} > \frac{MU_y}{p_y}\) and you would continue to buy more \(x\) (it’s a better value!) until your utility is maximized and you are at the optimum.
\[\frac{Income}{P_M}=\frac{\$240}{\$12}=20\]
See point A on graph above.
\[\frac{Income}{P_F}=\frac{\$240}{\$8}=30\]
See point B on graph above.
If Juan spends half of his $240 on music at $12 per stream: he buys \(\frac{\$120}{\$12}=10\) streams.
If Juan spends half of his $240 on fireworks at $8 per bag: he buys \(\frac{\$120}{\$8}=15\) bags.
This is point C on the graph above.
\[Slope=\frac{\Delta M}{\Delta F} = \frac{20}{30} = -\frac{2}{3}\]
\[\frac{m'}{p_F'}=\frac{\$360}{\$12}=30\]
\[\frac{m'}{p_M'}=\frac{\$360}{\$18}=20\]
This is the same budget constraint as before the income change, since income increased by 1.5x, and prices increased by 1.5x!
\[u(p,j) = 3pj\]
\[\begin{aligned} MU_p &= 3j\\ MU_j &= 3p\\ \end{aligned}\]
\[\begin{align*} MRS_{p,j}&=\frac{MU_p}{MU_j}\\ &=\frac{3j}{3p}\\ &=\frac{j}{p}\\ \end{align*}\]
Plug this combination into his utility function:
\[\begin{align*} u(p,j)&=3pj\\ u(4,1)&=3(4)(1)\\ &=12\\ \end{align*}\]
This is measuring the marginal utility of \(p\) and the marginal utility of \(j\), evaluated at his current consumption bundle of \(p=4\) and \(j=1\).
\[\begin{align*} MU_p&=3j\\ MU_p&=3(1)\\ MU_p&=3\\ \end{align*}\]
Consuming one additional unit of \(p\) will increase his utility by 3.
\[\begin{align*} MU_j&=3p\\ MU_j&=3(4)\\ MU_j&=12\\ \end{align*}\]
Consuming one additional unit of \(j\) will increase his utility by 12.
This is measuring his marginal rate of substitution (i.e. the slope of the indifference curve) evaluated at his current consumption bundle of \(p=4\) and \(j=1\). From part A, we found the equation for his \(MRS_{p,j}\):
\[\begin{align*} MRS_{p,j}&= \frac{j}{p}\\ MRS_{4,1}&= \frac{1}{4}\\ \end{align*}\]
At his current consumption bundle, he is willing to give up \(\frac{1}{4}\) units of \(j\) to obtain one more unit of \(p\) (and remain indifferent). This is the slope of the indifference curve at this point: to go one unit to the right, we go \(\frac{1}{4}\) units down.
To obtain one more unit of \(j\) and remain indifferent, he is willing to give up 4 units of \(p\). This is the inverse of the indifference curve slope at this point. Consider: to go up one unit, we go 4 units to the left.
Check the utility each bundle provides.
\[\begin{align*} u(p,j)&=3pj\\ u(4,1)&=3(4)(1)\\ u(4,1)&=12\\ \end{align*}\]
Bundle \(a\) provides utility of 12.
\[\begin{align*} u(p,j)&=3pj\\ u(2,2)&=3(2)(2)\\ u(2,2)&=12\\ \end{align*}\]
Bundle \(b\) provides utility of 12.
\[\begin{align*} u(p,j)&=3pj\\ u(1,4)&=3(1)(4)\\ u(1,4)&=12\\ \end{align*}\]
Bundle \(c\) provides utility of 12.
Since they all provide the same utility, he is indifferent between all three bundles: \(a \sim b \sim c\).
Check the utility this bundle provides.
\[\begin{align*} u(p,j)&=3pj\\ u(2,1)&=3(2)(1)\\ u(2,1)&=6\\ \end{align*}\]
Bundle \(d\) provides utility of 6. Since this is less than bundles \(a\), \(b\), and \(c\), he would prefer all of those over bundle \(d\): \(d \prec a \sim b \sim c\)
Kelly’s utility function for drinking Coke (\(c\)) and Pepsi (\(p\)) is given by:
\[\begin{aligned} u(c,p) &= 5c + 2p\\ MU_c &= 5\\ MU_p &= 2\\ \end{aligned}\]
Put Coke on the horizontal axis and Pepsi on the vertical axis.
Yes, because Coke and Pepsi are related by addition in the utility function. If \(c\) (or \(p\)) is 0, she can still get utility by consuming positive amounts of \(p\) (or \(c\)).
\[MRS_{C,P} = -\frac{MU_C}{MU_P} = -\frac{5}{2} = -2.5\]
Check by plugging in each point into the utility function:
\[u(c,p)=5c+2p\]
For (2,5):
\[u(c,p)=5(2)+2(5)=20\]
For (2,10)
\[u(c,p)=5(4)+2(0)= 20\]
Yes, because both bundles give the same utility (20).
MRS is constant, always -2.5!
Since MRS, the slope, is constant and unchanging, this is a straight line between the x-axis and y-axis. These goods are perfect substitutes: Kelly is always willing to trade 1 Coke for 2.5 Pepsi, or \(\frac{2}{5}\) Pepsi for 1 Coke.
\[u(x,y)=\sqrt{xy}\]
The idea is for you to see that there are multiple combinations of \(x\) and \(y\) that yield the same utility. These points are therefore on the same indifference curve.
The idea is to plot the values (whole numbers, 1, 2, 3) that have multiple \((x,y)\) combinations, and connect those values on the same curve.
\[\begin{aligned} MU_x&=0.5x^{-0.5}y^{0.5}\\ MU_y&=0.5x^{0.5}y^{-0.5}\\ \end{aligned}\]
We are given \(MU_X\) and \(MU_Y\), so:
\[MRS_{X,Y}=\frac{MU_X}{MU_Y}=\frac{0.5X^{-0.5}Y^{0.5}}{0.5X^{0.5}Y^{-0.5}}\]
Simplifying by exponent rules for division and for negative exponents:
\[\frac{0.5X^{-0.5}Y^{0.5}}{0.5X^{0.5}Y^{-0.5}}=\frac{0.5}{0.5}X^{(-0.5-0.5)}Y^{(0.5-[-0.5])}=X^{-1}Y^{1}=\frac{Y}{X}\]
\[\begin{aligned} m &= p_xx+p_yy \\ 10 &= 2.50x + 2.50y \\ 10-2.50x &= 2.50y \\ 4-x &= y \\ \end{aligned}\]
Budget constraint is graphed in black below.
At the optimum:
\[\frac{MU_x}{MU_y}=\frac{p_x}{p_y}\]
We already solved for the lefthand side in part (c), and we know the prices, so:
\[\begin{aligned} \left(\frac{Y}{X}\right)&=\frac{(2.50)}{(2.50)}\\ \frac{Y}{X}&=1\\ Y&=X\\ \end{aligned}\]
To find the exact quantities, plug this into the budget constraint:
\[\begin{aligned} m&=p_xx+p_yy\\ 10&=2.50x+2.50(x)\\ 10&=5x\\ x^*&=2\\ \end{aligned}\]
Since \(y=x\), \(y^*=2\)
The optimum is labeled \(A\) on the graph above.
\[\begin{aligned} u(x,y)&=\sqrt{xy}\\ u(2,2)&=\sqrt{2*2}\\ u(2,2)&=\sqrt{4}\\ u(2,2)&=2\\ \end{aligned}\]